What is the tangent of f(x)=6e^xcos(x),(0,6) ?

The tangent of f(x)=6e^xcos(x),(0,6) is y=6x+6

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tangent of f(x)=6e^xcos(x),(0,6)

tangent of

f (x) = 6 e^{x} cos (x), (0, 6)

y = 6 x + 6

Solution steps

Find the slope of

f (x) = 6 e^{x} cos (x) : \frac{df ( x )}{d x} = 6 (e^{x} cos (x) - e^{x} sin (x))

Compute the slope of

f (x) = 6 e^{x} cos (x)

(0, 6) : m = 6

Find the line with slope m=

6

and passing through

(0, 6) : y = 6 x + 6

y = 6 x + 6

\frac{d ^{2}}{d x ^{2}} (3 csc (x))

\frac{\partial}{\partial x} (cos (x^{2} + x y))

x \to 5 + lim (\frac{x ^{2} + 2}{5 - x})

n = 3 \sum \infty \frac{6}{n ^{2} - 1}

x^{5} + y^{5} = 10

What is the tangent of f(x)=6e^xcos(x),(0,6) ?
The tangent of f(x)=6e^xcos(x),(0,6) is y=6x+6