What is the limit as x approaches 1-of (\sqrt[3]{x+65}-4)/(x+1) ?

The limit as x approaches 1-of (\sqrt[3]{x+65}-4)/(x+1) is (\sqrt[3]{66}-4)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 1-of (\sqrt[3]{x+65}-4)/(x+1)

x \to 1 - lim (\frac{3 x + 65 - 4}{x + 1})

\frac{3 66 - 4}{2}

Decimal

0.02062 \dots

Solution steps

x \to 1 - lim (\frac{3 x + 65 - 4}{x + 1})

Plug in the value

x = 1

= \frac{3 1 + 65 - 4}{1 + 1}

Simplify

= \frac{3 66 - 4}{2}

x \to 0 lim ([x (x - 2)])

x \to - 5 lim (- 2 x - 5)

x \to \frac{π}{6} lim (sin^{x} (x))

x \to 1 lim (3^{\frac{1}{x - 1}})

x \to 1 lim (\frac{( e ^{x} )}{x ^{4}})

What is the limit as x approaches 1-of (\sqrt[3]{x+65}-4)/(x+1) ?
The limit as x approaches 1-of (\sqrt[3]{x+65}-4)/(x+1) is (\sqrt[3]{66}-4)/2