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Popular >

((-3cos(2x)-sin(3x)-4)^2)^'

Solution

((- 3 cos (2 x) - sin (3 x) - 4)^{2})^{^{'}}

Solution

2 (- 3 cos (2 x) - sin (3 x) - 4) (6 sin (2 x) - 3 cos (3 x))

Solution steps

((- 3 cos (2 x) - sin (3 x) - 4)^{2})^{'}

Apply the chain rule:

2 (- 3 cos (2 x) - sin (3 x) - 4) (- 3 cos (2 x) - sin (3 x) - 4)^{'}

= 2 (- 3 cos (2 x) - sin (3 x) - 4) (- 3 cos (2 x) - sin (3 x) - 4)^{'}

(- 3 cos (2 x) - sin (3 x) - 4)^{'} = 6 sin (2 x) - 3 cos (3 x)

= 2 (- 3 cos (2 x) - sin (3 x) - 4) (6 sin (2 x) - 3 cos (3 x))

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Frequently Asked Questions (FAQ)

What is the ((-3cos(2x)-sin(3x)-4)^2)^' ?
The ((-3cos(2x)-sin(3x)-4)^2)^' is 2(-3cos(2x)-sin(3x)-4)(6sin(2x)-3cos(3x))
What is the first ((-3cos(2x)-sin(3x)-4)^2)^' ?
The first ((-3cos(2x)-sin(3x)-4)^2)^' is 2(-3cos(2x)-sin(3x)-4)(6sin(2x)-3cos(3x))