What is the limit as x approaches 0 of 2sin(3x) ?

The limit as x approaches 0 of 2sin(3x) is 0

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limit as x approaches 0 of 2sin(3x)

x \to 0 lim (2 sin (3 x))

0

Solution steps

x \to 0 lim (2 sin (3 x))

Plug in the value

x = 0

= 2 sin (3 \cdot 0)

Simplify

2 sin (3 \cdot 0) : 0

= 0

x \to 0 + lim (x ln (7 x))

x \to 0 lim (- 9)

x \to 2 - lim (\frac{x ^{2} + 5}{x + 1})

x \to 8 + lim (\frac{1}{8 - x})

x \to 2 lim (5^{x})

What is the limit as x approaches 0 of 2sin(3x) ?
The limit as x approaches 0 of 2sin(3x) is 0