What is the limit as (x) approaches (0) of sin(1/x) ?

The limit as (x) approaches (0) of sin(1/x) is diverges

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limit as (x) approaches (0) of sin(1/x)

(x) \to (0) lim (sin (\frac{1}{x}))

diverges

Solution steps

x \to 0 lim (sin (\frac{1}{x}))

Apply Limit Divergence Criterion:

diverges

= diverges

x \to 1 lim (\frac{3 ^{x} - 3}{x - 1})

x \to 0 lim (\frac{π}{4})

x \to 0 + lim (x^{3 x^{2}})

x \to 1 lim (\frac{5 ln ( x )}{x})

x \to 2 lim (\frac{x ^{2} - x}{x + 2})

What is the limit as (x) approaches (0) of sin(1/x) ?
The limit as (x) approaches (0) of sin(1/x) is diverges