What is the limit as x approaches 0+of 3x^2ln(x) ?

The limit as x approaches 0+of 3x^2ln(x) is 0

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limit as x approaches 0+of 3x^2ln(x)

x \to 0 + lim (3 x^{2} ln (x))

0

Solution steps

x \to 0 + lim (3 x^{2} ln (x))

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= 3 \cdot x \to 0 + lim (x^{2} ln (x))

Rewrite for L'Hopital

= 3 \cdot x \to 0 + lim (\frac{ln ( x )}{\frac{1}{x ^{2}}})

Apply L'Hopital's Rule

: x \to 0 + lim (\frac{\frac{1}{x}}{- \frac{2}{x ^{3}}})

= 3 \cdot x \to 0 + lim (\frac{\frac{1}{x}}{- \frac{2}{x ^{3}}})

Simplify

\frac{\frac{1}{x}}{- \frac{2}{x ^{3}}} : - \frac{x ^{2}}{2}

= 3 \cdot x \to 0 + lim (- \frac{x ^{2}}{2})

Plug in the value

x = 0

= 3 (- \frac{0 ^{2}}{2})

Simplify

3 (- \frac{0 ^{2}}{2}) : 0

= 0

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What is the limit as x approaches 0+of 3x^2ln(x) ?
The limit as x approaches 0+of 3x^2ln(x) is 0