What is the solution for (2+x)y^'=3y ?

The solution for (2+x)y^'=3y is y=8e^{c_{1}}+12e^{c_{1}}x+6e^{c_{1}}x^2+e^{c_{1}}x^3

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(2+x)y^'=3y

(2 + x) y^{^{'}} = 3 y

y = 8 e^{c_{1}} + 12 e^{c_{1}} x + 6 e^{c_{1}} x^{2} + e^{c_{1}} x^{3}

Solution steps

(2 + x) y^{'} (x) = 3 y

Solve separable ODE:

y = 8 e^{c_{1}} + 12 e^{c_{1}} x + 6 e^{c_{1}} x^{2} + e^{c_{1}} x^{3}

y = 8 e^{c_{1}} + 12 e^{c_{1}} x + 6 e^{c_{1}} x^{2} + e^{c_{1}} x^{3}

\frac{\partial}{\partial x} (20 x y)

\int_{0}^{2} \frac{1}{4 + t ^{2}} d t

(34) (3 - 4)

\frac{d}{d x} (x^{2} + x y + y^{3})

cos (x)

What is the solution for (2+x)y^'=3y ?
The solution for (2+x)y^'=3y is y=8e^{c_{1}}+12e^{c_{1}}x+6e^{c_{1}}x^2+e^{c_{1}}x^3