What is the limit as x approaches 1+of (ln(x))^x ?

The limit as x approaches 1+of (ln(x))^x is 0

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limit as x approaches 1+of (ln(x))^x

x \to 1 + lim ((ln (x))^{x})

0

Solution steps

x \to 1 + lim ((ln (x))^{x})

Plug in the value

x = 1

= (ln (1))^{1}

Simplify

ln^{1} (1) : 0

= 0

x \to - 2 lim (\frac{5 x}{2 x + 4})

x \to - 1 lim (x^{2} + 2 x + 2)

x \to 3 + lim (10 - 2 x)

x \to 0 lim (3 x - x^{2})

x \to 0 lim (\frac{sin ( p ) x}{x})

What is the limit as x approaches 1+of (ln(x))^x ?
The limit as x approaches 1+of (ln(x))^x is 0