What is the solution for y^{''}+36y=36sin(6x) ?

The solution for y^{''}+36y=36sin(6x) is y=c_{1}cos(6x)+c_{2}sin(6x)-3xcos(6x)

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y^{''}+36y=36sin(6x)

y^{^{''}} + 36 y = 36 sin (6 x)

y = c_{1} cos (6 x) + c_{2} sin (6 x) - 3 x cos (6 x)

Solution steps

y^{''} (x) + 36 y = 36 sin (6 x)

Solve linear ODE:

y = c_{1} cos (6 x) + c_{2} sin (6 x) - 3 x cos (6 x)

y = c_{1} cos (6 x) + c_{2} sin (6 x) - 3 x cos (6 x)

\int \frac{324 - x ^{2}}{x} d x

\frac{\partial}{\partial x} (- 2 x)

\frac{\partial}{\partial y} (x^{2} + x y^{3})

5 \frac{d y}{d t} + y = 20 t

\int e^{5 - 2 x} d x

What is the solution for y^{''}+36y=36sin(6x) ?
The solution for y^{''}+36y=36sin(6x) is y=c_{1}cos(6x)+c_{2}sin(6x)-3xcos(6x)