What is the derivative of (2^x)^2 ?

The derivative of (2^x)^2 is ln(2)*2^{2x+1}

What is the first derivative of (2^x)^2 ?

The first derivative of (2^x)^2 is ln(2)*2^{2x+1}

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derivative of

(2^{x})^{2}

ln (2) \cdot 2^{2 x + 1}

Solution steps

\frac{d}{d x} ((2^{x})^{2})

Simplify

(2^{x})^{2} : 4^{x}

= \frac{d}{d x} (4^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 4^{x} ln (4)

Simplify

4^{x} ln (4) : ln (2) \cdot 2^{2 x + 1}

= ln (2) \cdot 2^{2 x + 1}

lo g_{10} (1 + x)

sin^{2} (x^{2} + 1)

\frac{( x ^{2} + 1 )}{x}

\frac{x ^{5}}{2}

(\frac{x + 1}{x})^{2}

What is the derivative of (2^x)^2 ?
The derivative of (2^x)^2 is ln(2)*2^{2x+1}
What is the first derivative of (2^x)^2 ?
The first derivative of (2^x)^2 is ln(2)*2^{2x+1}