What is the derivative of 1/((x+1)) ?

The derivative of 1/((x+1)) is -1/((x+1)^2)

What is the first derivative of 1/((x+1)) ?

The first derivative of 1/((x+1)) is -1/((x+1)^2)

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derivative of

\frac{1}{( x + 1 )}

- \frac{1}{( x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{x + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x + 1)^{- 1})

Apply the chain rule:

- \frac{1}{( x + 1 ) ^{2}} \frac{d}{d x} (x + 1)

= - \frac{1}{( x + 1 ) ^{2}} \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= - \frac{1}{( x + 1 ) ^{2}} \cdot 1

Simplify

= - \frac{1}{( x + 1 ) ^{2}}

\frac{1}{( x ^{2} + a ^{2} )}

y = (1 0^{x})^{2}

x^{3} + 6 x^{2} + 12 x - 13

lo g_{10} (\frac{1}{x})

(2 x + 3)^{5} (3 - x)^{4}

What is the derivative of 1/((x+1)) ?
The derivative of 1/((x+1)) is -1/((x+1)^2)
What is the first derivative of 1/((x+1)) ?
The first derivative of 1/((x+1)) is -1/((x+1)^2)