What is the derivative of x^2ln(x+x^3) ?

The derivative of x^2ln(x+x^3) is 2xln(x)+x+3x^2

What is the first derivative of x^2ln(x+x^3) ?

The first derivative of x^2ln(x+x^3) is 2xln(x)+x+3x^2

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\frac{d}{d x} (x^{2} ln (x) + x^{3})

2 x ln (x) + x + 3 x^{2}

Solution steps

\frac{d}{d x} (x^{2} ln (x) + x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2} ln (x)) + \frac{d}{d x} (x^{3})

\frac{d}{d x} (x^{2} ln (x)) = 2 x ln (x) + x

\frac{d}{d x} (x^{3}) = 3 x^{2}

= 2 x ln (x) + x + 3 x^{2}

\frac{d y}{d x} (x) = y

\frac{\partial}{\partial x} ((x - a)^{2})

\int \frac{1}{2 x + 6} d x

\int cos (p i x) d x

\frac{d y}{d x} + 4 y = x e^{- 4 x}

What is the derivative of x^2ln(x+x^3) ?
The derivative of x^2ln(x+x^3) is 2xln(x)+x+3x^2
What is the first derivative of x^2ln(x+x^3) ?
The first derivative of x^2ln(x+x^3) is 2xln(x)+x+3x^2