What is the derivative of x^{sin^2(x)} ?

The derivative of x^{sin^2(x)} is x^{sin^2(x)}(sin(2x)ln(x)+(sin^2(x))/x)

What is the first derivative of x^{sin^2(x)} ?

The first derivative of x^{sin^2(x)} is x^{sin^2(x)}(sin(2x)ln(x)+(sin^2(x))/x)

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derivative of

x^{s i n^{2} (x)}

x^{s i n^{2} (x)} (sin (2 x) ln (x) + \frac{sin ^{2} ( x )}{x})

Solution steps

\frac{d}{d x} (x^{s i n^{2} (x)})

Apply exponent rule:

a^{b} = e^{b l n (a)}

x^{s i n^{2} (x)} = e^{s i n^{2} (x) l n (x)}

= \frac{d}{d x} (e^{s i n^{2} (x) l n (x)})

Apply the chain rule:

e^{s i n^{2} (x) l n (x)} \frac{d}{d x} (sin^{2} (x) ln (x))

= e^{s i n^{2} (x) l n (x)} \frac{d}{d x} (sin^{2} (x) ln (x))

\frac{d}{d x} (sin^{2} (x) ln (x)) = sin (2 x) ln (x) + \frac{sin ^{2} ( x )}{x}

= e^{s i n^{2} (x) l n (x)} (sin (2 x) ln (x) + \frac{sin ^{2} ( x )}{x})

e^{s i n^{2} (x) l n (x)} = x^{s i n^{2} (x)}

= x^{s i n^{2} (x)} (sin (2 x) ln (x) + \frac{sin ^{2} ( x )}{x})

\frac{d}{df} (\frac{( f ( 1 ) + f ( 4 ) )}{( - 3 f ( 0 ) )})

e^{x^{2} + y^{2}}

y = - 10 x + 7

\frac{d}{d n} ((2 n - 1)!!)

\frac{1 - e ^{x}}{1 + e ^{x}}

What is the derivative of x^{sin^2(x)} ?
The derivative of x^{sin^2(x)} is x^{sin^2(x)}(sin(2x)ln(x)+(sin^2(x))/x)
What is the first derivative of x^{sin^2(x)} ?
The first derivative of x^{sin^2(x)} is x^{sin^2(x)}(sin(2x)ln(x)+(sin^2(x))/x)