What is the derivative of e^2x+1 ?

The derivative of e^2x+1 is e^2

What is the first derivative of e^2x+1 ?

The first derivative of e^2x+1 is e^2

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derivative of

e^{2} x + 1

e^{2}

Solution steps

\frac{d}{d x} (e^{2} x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{2} x) + \frac{d}{d x} (1)

\frac{d}{d x} (e^{2} x) = e^{2}

\frac{d}{d x} (1) = 0

= e^{2} + 0

Simplify

= e^{2}

f (x) = \frac{( x ^{2} + x )}{( 2 x - 1 )}

(3 x^{2} - 1) (2 x + 3)

(2^{x})^{x}

(e^{x})^{- 2}

\frac{( e ^{x} + 1 )}{( e ^{x} - 1 )}