What is the derivative of 1+ln(x) ?

The derivative of 1+ln(x) is 1/x

What is the first derivative of 1+ln(x) ?

The first derivative of 1+ln(x) is 1/x

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derivative of

1 + ln (x)

\frac{1}{x}

Solution steps

\frac{d}{d x} (1 + ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (ln (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 0 + \frac{1}{x}

Simplify

= \frac{1}{x}

7 x^{5} + 17

x^{3} - 3 x - 5

\frac{x ^{2}}{tan ( x )}

y = 4 cos (4 x^{2})

\frac{d}{d x} \frac{( x y )}{( x ^{2} + y ^{2} )}

What is the derivative of 1+ln(x) ?
The derivative of 1+ln(x) is 1/x
What is the first derivative of 1+ln(x) ?
The first derivative of 1+ln(x) is 1/x