What is the first derivative of 3x^2-1 ?

The first derivative of 3x^2-1 is 6x

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derivative of 3x^2-1

derivative of

3 x^{2} - 1

6 x

Solution steps

\frac{d}{d x} (3 x^{2} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (1)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (1) = 0

= 6 x - 0

Simplify

= 6 x

e^{2} x + 3

sin^{2} (2 x + 1)

f (x) = 3 x^{2} + 2 x - 1

f (x) = 4 + x

\frac{x ^{3}}{( 1 + x ^{3} )}