What is the derivative of ((x+1))/x ?

The derivative of ((x+1))/x is -1/(x^2)

What is the first derivative of ((x+1))/x ?

The first derivative of ((x+1))/x is -1/(x^2)

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derivative of

\frac{( x + 1 )}{x}

- \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{x + 1}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x + 1 ) x - \frac{d x}{d x} ( x + 1 )}{x ^{2}}

\frac{d}{d x} (x + 1) = 1

\frac{d x}{d x} = 1

= \frac{1 \cdot x - 1 \cdot ( x + 1 )}{x ^{2}}

Simplify

\frac{1 \cdot x - 1 \cdot ( x + 1 )}{x ^{2}} : - \frac{1}{x ^{2}}

= - \frac{1}{x ^{2}}

\frac{1}{e ^{y} - x}

3 x^{2} + 99 x + lo g_{10} (x)

\frac{3}{x ^{2}} + \frac{4}{x}

\frac{d}{d f} (\frac{f + 2}{g})

\frac{- x}{3}

What is the derivative of ((x+1))/x ?
The derivative of ((x+1))/x is -1/(x^2)
What is the first derivative of ((x+1))/x ?
The first derivative of ((x+1))/x is -1/(x^2)