What is the integral from 0.1 to 1 of 1.5x^2 ?

The integral from 0.1 to 1 of 1.5x^2 is 0.4995

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integral from 0.1 to 1 of 1.5x^2

\int_{0.1}^{1} 1.5 x^{2} d x

0.4995

Solution steps

\int_{0.1}^{1} 1.5 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 1.5 \cdot \int_{0.1}^{1} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0.1}^{1}

= 1.5 [\frac{x ^{3}}{3}]_{0.1}^{1}

Simplify

= 1.5 [0.33333 \dots x^{3}]_{0.1}^{1}

Compute the boundaries:

0.333

= 1.5 \cdot 0.333

Simplify

= 0.4995

x \to 4 lim (\frac{x}{- 7 x + 1})

\frac{\partial}{\partial x} (x^{2} ln (x y))

\int_{1}^{x} e^{x^{2}} d x

\frac{d}{d x} (12 x^{2} - 12 x)

\frac{d}{d j} (4 i + 5 j)

What is the integral from 0.1 to 1 of 1.5x^2 ?
The integral from 0.1 to 1 of 1.5x^2 is 0.4995