What is the derivative of 2cos(2x-1) ?

The derivative of 2cos(2x-1) is -4sin(2x-1)

What is the first derivative of 2cos(2x-1) ?

The first derivative of 2cos(2x-1) is -4sin(2x-1)

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derivative of

2 cos (2 x - 1)

- 4 sin (2 x - 1)

Solution steps

\frac{d}{d x} (2 cos (2 x - 1))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (cos (2 x - 1))

Apply the chain rule:

- sin (2 x - 1) \frac{d}{d x} (2 x - 1)

= - sin (2 x - 1) \frac{d}{d x} (2 x - 1)

\frac{d}{d x} (2 x - 1) = 2

= 2 (- sin (2 x - 1) \cdot 2)

Simplify

= - 4 sin (2 x - 1)

x^{2} x

\frac{cot ( x )}{2}

(e^{x})^{- 1}

lo g_{10} (1) + x

lo g_{10} (1) - x

What is the derivative of 2cos(2x-1) ?
The derivative of 2cos(2x-1) is -4sin(2x-1)
What is the first derivative of 2cos(2x-1) ?
The first derivative of 2cos(2x-1) is -4sin(2x-1)