What is the derivative of ln((e^x)^2) ?

The derivative of ln((e^x)^2) is 2

What is the first derivative of ln((e^x)^2) ?

The first derivative of ln((e^x)^2) is 2

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derivative of

ln ((e^{x})^{2})

2

Solution steps

\frac{d}{d x} (ln ((e^{x})^{2}))

Simplify

ln ((e^{x})^{2}) : 2 x

= \frac{d}{d x} (2 x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d x}{d x}

Apply the common derivative:

\frac{d x}{d x} = 1

= 2 \cdot 1

Simplify

= 2

x y^{\frac{1}{3}}

\frac{d}{d t} (10 + 3 t)

6 x^{2} + 12 x - 13

y = \frac{x}{( x + 1 ) ^{2}}

\frac{d}{d q} (\frac{( tan ( q ) )}{( 1 + tan ( q ) )})

What is the derivative of ln((e^x)^2) ?
The derivative of ln((e^x)^2) is 2
What is the first derivative of ln((e^x)^2) ?
The first derivative of ln((e^x)^2) is 2