What is the derivative of 3x-cos(x)-1 ?

The derivative of 3x-cos(x)-1 is sin(x)+3

What is the first derivative of 3x-cos(x)-1 ?

The first derivative of 3x-cos(x)-1 is sin(x)+3

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derivative of

3 x - cos (x) - 1

sin (x) + 3

Solution steps

\frac{d}{d x} (3 x - cos (x) - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) - \frac{d}{d x} (cos (x)) - \frac{d}{d x} (1)

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (cos (x)) = - sin (x)

\frac{d}{d x} (1) = 0

= 3 - (- sin (x)) - 0

Simplify

= sin (x) + 3

\frac{d}{d t} (10 + 2 t)

y = 2 e^{3}

(x^{2} + 3)^{4} (x + 1)

(2 x + 5)^{\frac{1}{3}}

2 x^{3} - 4 x^{5} + 8 + 7 x^{2}

What is the derivative of 3x-cos(x)-1 ?
The derivative of 3x-cos(x)-1 is sin(x)+3
What is the first derivative of 3x-cos(x)-1 ?
The first derivative of 3x-cos(x)-1 is sin(x)+3