What is the derivative of (-1)/(t^2) ?

The derivative of (-1)/(t^2) is 2/(t^3)

What is the first derivative of (-1)/(t^2) ?

The first derivative of (-1)/(t^2) is 2/(t^3)

Popular >

derivative of

\frac{- 1}{t ^{2}}

\frac{2}{t ^{3}}

Solution steps

\frac{d}{d t} (\frac{- 1}{t ^{2}})

Simplify

\frac{- 1}{t ^{2}} : - \frac{1}{t ^{2}}

= \frac{d}{d t} (- \frac{1}{t ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d t} (\frac{1}{t ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - \frac{d}{d t} (t^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - (- 2 t^{- 2 - 1})

Simplify

- (- 2 t^{- 2 - 1}) : \frac{2}{t ^{3}}

= \frac{2}{t ^{3}}

e^{\frac{- 1}{x ^{2}}}

\frac{1}{( x ^{2} + y ^{2} )}

(\frac{x + 1}{x})^{3}

\frac{d}{d x} ((x - h)^{2} + k)

f (x) = \frac{1}{( 2 x ^{2} )}

What is the derivative of (-1)/(t^2) ?
The derivative of (-1)/(t^2) is 2/(t^3)
What is the first derivative of (-1)/(t^2) ?
The first derivative of (-1)/(t^2) is 2/(t^3)