What is the derivative of f(x)=-2x^2-5 ?

The derivative of f(x)=-2x^2-5 is -4x

What is the first derivative of f(x)=-2x^2-5 ?

The first derivative of f(x)=-2x^2-5 is -4x

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derivative of

f (x) = - 2 x^{2} - 5

- 4 x

Solution steps

\frac{d}{d x} (- 2 x^{2} - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (5)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (5) = 0

= - 4 x - 0

Simplify

= - 4 x

cosh^{2} (x)

3 x^{2} + 5 x - 2

lo g_{10} (x^{2} - 1)

(x^{2} + 1)^{4}

\frac{d}{d x} ((a + 3) \cdot x^{2} + (b - 2) \cdot x + c)

What is the derivative of f(x)=-2x^2-5 ?
The derivative of f(x)=-2x^2-5 is -4x
What is the first derivative of f(x)=-2x^2-5 ?
The first derivative of f(x)=-2x^2-5 is -4x