What is the derivative of (3^x)^2 ?

The derivative of (3^x)^2 is 2ln(3)*9^x

What is the first derivative of (3^x)^2 ?

The first derivative of (3^x)^2 is 2ln(3)*9^x

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derivative of

(3^{x})^{2}

2 ln (3) \cdot 9^{x}

Solution steps

\frac{d}{d x} ((3^{x})^{2})

Simplify

(3^{x})^{2} : 9^{x}

= \frac{d}{d x} (9^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 9^{x} ln (9)

Simplify

ln (9) : 2 ln (3)

= 2 ln (3) \cdot 9^{x}

\frac{d}{d s} (3 s)

[f (x)]^{2}

x tan (3 x^{2} + 4 x + 1)

tan (2 x) + sec (3 x)

x^{2} (x + 1)

What is the derivative of (3^x)^2 ?
The derivative of (3^x)^2 is 2ln(3)*9^x
What is the first derivative of (3^x)^2 ?
The first derivative of (3^x)^2 is 2ln(3)*9^x