What is the derivative of |x+2|-1 ?

The derivative of |x+2|-1 is (x+2)/(|x+2|)

What is the first derivative of |x+2|-1 ?

The first derivative of |x+2|-1 is (x+2)/(|x+2|)

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derivative of

∣ x + 2 ∣ - 1

\frac{x + 2}{∣ x + 2 ∣}

Solution steps

\frac{d}{d x} (∣ x + 2 ∣ - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (∣ x + 2 ∣) - \frac{d}{d x} (1)

\frac{d}{d x} (∣ x + 2 ∣) = \frac{x + 2}{∣ x + 2 ∣}

\frac{d}{d x} (1) = 0

= \frac{x + 2}{∣ x + 2 ∣} - 0

Simplify

= \frac{x + 2}{∣ x + 2 ∣}

\frac{a}{x ^{2}}

y = 6 x - 3

- \frac{x}{4} + \frac{3}{4}

x + 2 y

x^{1} + n

What is the derivative of |x+2|-1 ?
The derivative of |x+2|-1 is (x+2)/(|x+2|)
What is the first derivative of |x+2|-1 ?
The first derivative of |x+2|-1 is (x+2)/(|x+2|)