What is the first derivative of y^1-n ?

The first derivative of y^1-n is 1

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derivative of y^1-n

derivative of

y^{1} - n

1

Solution steps

\frac{d}{d y} (y^{1} - n)

Simplify

y^{1} - n : y - n

= \frac{d}{d y} (y - n)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d y}{d y} - \frac{d n}{d y}

\frac{d y}{d y} = 1

\frac{d n}{d y} = 0

= 1 - 0

Simplify

= 1

(1 + x)^{x}

\frac{3}{cos ( x )}

2 x (1 + 3 x^{2})^{3}

y = (2 x + 1)^{5}

(4 - 3 x^{2})^{5}