What is the d/(dp)(140p^{1/3}) ?

The d/(dp)(140p^{1/3}) is (140)/(3p^{2/3)}

What is the first d/(dp)(140p^{1/3}) ?

The first d/(dp)(140p^{1/3}) is (140)/(3p^{2/3)}

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\frac{d}{d p} (140 p^{\frac{1}{3}})

\frac{140}{3 p ^{\frac{2}{3}}}

Solution steps

\frac{d}{d p} (140 p^{\frac{1}{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 140 \frac{d}{d p} (p^{\frac{1}{3}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 140 \cdot \frac{1}{3} p^{\frac{1}{3} - 1}

Simplify

140 \cdot \frac{1}{3} p^{\frac{1}{3} - 1} : \frac{140}{3 p ^{\frac{2}{3}}}

= \frac{140}{3 p ^{\frac{2}{3}}}

\frac{d}{dd} (n (1 - d \cdot n))

\frac{- x ^{3}}{3}

tan (3 x + 2)

\frac{( 1 - x ^{2} )}{( 1 + x ^{2} )}

\frac{x}{( x + 1 )}

What is the d/(dp)(140p^{1/3}) ?
The d/(dp)(140p^{1/3}) is (140)/(3p^{2/3)}
What is the first d/(dp)(140p^{1/3}) ?
The first d/(dp)(140p^{1/3}) is (140)/(3p^{2/3)}