What is the derivative of 3x^2y^2 ?

The derivative of 3x^2y^2 is 6xy^2

What is the first derivative of 3x^2y^2 ?

The first derivative of 3x^2y^2 is 6xy^2

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derivative of

3 x^{2} y^{2}

6 x y^{2}

Solution steps

\frac{d}{d x} (3 x^{2} y^{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 y^{2} \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 y^{2} \cdot 2 x^{2 - 1}

Simplify

= 6 x y^{2}

\frac{e ^{2} x}{2}

lo g_{10} ((3 x + 2)^{3})

cos^{2} (\frac{x}{2})

\frac{d}{d t} (\frac{1}{2 \cdot a \cdot t ^{2}})

y = \frac{1}{x ^{2} + x ^{2}}

What is the derivative of 3x^2y^2 ?
The derivative of 3x^2y^2 is 6xy^2
What is the first derivative of 3x^2y^2 ?
The first derivative of 3x^2y^2 is 6xy^2