What is the derivative of 1+log_{10}(x) ?

The derivative of 1+log_{10}(x) is 1/(ln(10)x)

What is the first derivative of 1+log_{10}(x) ?

The first derivative of 1+log_{10}(x) is 1/(ln(10)x)

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derivative of

1 + lo g_{10} (x)

\frac{1}{ln ( 10 ) x}

Solution steps

\frac{d}{d x} (1 + lo g_{10} (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (lo g_{10} (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (lo g_{10} (x)) = \frac{1}{x ln ( 10 )}

= 0 + \frac{1}{x ln ( 10 )}

Simplify

= \frac{1}{ln ( 10 ) x}

\frac{d}{d x} (\frac{2}{( 1 + a \cdot e ^{b \cdot x^{2}} )})

ln (4 - 2 cos (x))

\frac{1}{[ e ^{\frac{c}{x}} - 1 ]}

\frac{1}{( x + 2 )}

2 x - lo g_{10} (x) - 7

What is the derivative of 1+log_{10}(x) ?
The derivative of 1+log_{10}(x) is 1/(ln(10)x)
What is the first derivative of 1+log_{10}(x) ?
The first derivative of 1+log_{10}(x) is 1/(ln(10)x)