What is the derivative of sin(x^3-2x^2) ?

The derivative of sin(x^3-2x^2) is cos(x^3-2x^2)(3x^2-4x)

What is the first derivative of sin(x^3-2x^2) ?

The first derivative of sin(x^3-2x^2) is cos(x^3-2x^2)(3x^2-4x)

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derivative of

sin (x^{3} - 2 x^{2})

cos (x^{3} - 2 x^{2}) (3 x^{2} - 4 x)

Solution steps

\frac{d}{d x} (sin (x^{3} - 2 x^{2}))

Apply the chain rule:

cos (x^{3} - 2 x^{2}) \frac{d}{d x} (x^{3} - 2 x^{2})

= cos (x^{3} - 2 x^{2}) \frac{d}{d x} (x^{3} - 2 x^{2})

\frac{d}{d x} (x^{3} - 2 x^{2}) = 3 x^{2} - 4 x

= cos (x^{3} - 2 x^{2}) (3 x^{2} - 4 x)

- sin^{2} (x)

(1 - x)^{- 1}

x^{8} + x^{\frac{1}{8}}

2 cos (2 + x^{3})

lo g_{10} (x^{2} + x + 1)

What is the derivative of sin(x^3-2x^2) ?
The derivative of sin(x^3-2x^2) is cos(x^3-2x^2)(3x^2-4x)
What is the first derivative of sin(x^3-2x^2) ?
The first derivative of sin(x^3-2x^2) is cos(x^3-2x^2)(3x^2-4x)