What is derivative of f(x)= 4/t-1/6 t^3+8/(t^5) ?

The answer to derivative of f(x)= 4/t-1/6 t^3+8/(t^5) is (dt)/(dx)=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of f(x)= 4/t-1/6 t^3+8/(t^5)

derivative of

f (x) = \frac{4}{t} - \frac{1}{6} t^{3} + \frac{8}{t ^{5}}

\frac{d t}{d x} = 0

Solution steps

f (x) = \frac{4}{t} - \frac{1}{6} t^{3} + \frac{8}{t ^{5}}

Treat

t

t (x)

Differentiate both sides:

0 = - \frac{4 \frac{d t}{d x}}{t ^{2}} - \frac{t ^{2} \frac{d t}{d x}}{2} - \frac{40 \frac{d t}{d x}}{t ^{6}}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

3 x^{2} (1 - x)^{3}

\frac{d}{d x} (x^{2} y i + y^{3} z j - z^{2} x k)

(\frac{1 + 1}{x})^{x}

2 x^{20}

\frac{d}{d x} (- 100 + 177.5 - 1.5 (x - 30))

What is derivative of f(x)= 4/t-1/6 t^3+8/(t^5) ?
The answer to derivative of f(x)= 4/t-1/6 t^3+8/(t^5) is (dt)/(dx)=0