What is the derivative of ((x+1))/2 ?

The derivative of ((x+1))/2 is 1/2

What is the first derivative of ((x+1))/2 ?

The first derivative of ((x+1))/2 is 1/2

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derivative of

\frac{( x + 1 )}{2}

\frac{1}{2}

Solution steps

\frac{d}{d x} (\frac{x + 1}{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{2} (\frac{d x}{d x} + \frac{d}{d x} (1))

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= \frac{1}{2} (1 + 0)

Simplify

= \frac{1}{2}

\frac{d}{d t} (2 cos (12 t))

\frac{( x ^{2} - 2 x )}{( x - 1 ) ^{2}}

y = \frac{2 x ^{2} - x + 4}{x}

(cos^{22} (x)) (1 - x)^{- 2}

x (x^{2} - 1)^{\frac{1}{2}}

What is the derivative of ((x+1))/2 ?
The derivative of ((x+1))/2 is 1/2
What is the first derivative of ((x+1))/2 ?
The first derivative of ((x+1))/2 is 1/2