What is the first d/(dt)(-10+2.5t) ?

The first d/(dt)(-10+2.5t) is 2.5

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d/(dt)(-10+2.5t)

\frac{d}{d t} (- 10 + 2.5 t)

2.5

Solution steps

\frac{d}{d t} (- 10 + 2.5 t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d t} (10) + \frac{d}{d t} (2.5 t)

\frac{d}{d t} (10) = 0

\frac{d}{d t} (2.5 t) = 2.5

= - 0 + 2.5

Simplify

= 2.5

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