What is the derivative of x/((x^2+4)^2) ?

The derivative of x/((x^2+4)^2) is (-3x^2+4)/((x^2+4)^3)

What is the first derivative of x/((x^2+4)^2) ?

The first derivative of x/((x^2+4)^2) is (-3x^2+4)/((x^2+4)^3)

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derivative of

\frac{x}{( x ^{2} + 4 ) ^{2}}

\frac{- 3 x ^{2} + 4}{( x ^{2} + 4 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{x}{( x ^{2} + 4 ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d x}{d x} ( x ^{2} + 4 ) ^{2} - \frac{d}{d x} ( ( x ^{2} + 4 ) ^{2} ) x}{( ( x ^{2} + 4 ) ^{2} ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} ((x^{2} + 4)^{2}) = 4 x (x^{2} + 4)

= \frac{1 \cdot ( x ^{2} + 4 ) ^{2} - 4 x ( x ^{2} + 4 ) x}{( ( x ^{2} + 4 ) ^{2} ) ^{2}}

Simplify

\frac{1 \cdot ( x ^{2} + 4 ) ^{2} - 4 x ( x ^{2} + 4 ) x}{( ( x ^{2} + 4 ) ^{2} ) ^{2}} : \frac{- 3 x ^{2} + 4}{( x ^{2} + 4 ) ^{3}}

= \frac{- 3 x ^{2} + 4}{( x ^{2} + 4 ) ^{3}}

(x + 3)^{\frac{1}{2}}

tan^{2} (x - 1)

y = \frac{1}{x ^{2} + x}

3^{x} \cdot x^{3}

2^{c o s^{2} (x)}

What is the derivative of x/((x^2+4)^2) ?
The derivative of x/((x^2+4)^2) is (-3x^2+4)/((x^2+4)^3)
What is the first derivative of x/((x^2+4)^2) ?
The first derivative of x/((x^2+4)^2) is (-3x^2+4)/((x^2+4)^3)