What is the d/(dq)((5+1)/((cot(q)))) ?

The d/(dq)((5+1)/((cot(q)))) is 6sec^2(q)

What is the first d/(dq)((5+1)/((cot(q)))) ?

The first d/(dq)((5+1)/((cot(q)))) is 6sec^2(q)

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\frac{d}{d q} (\frac{5 + 1}{( cot ( q ) )})

6 sec^{2} (q)

Solution steps

\frac{d}{d q} (\frac{5 + 1}{( cot ( q ) )})

Simplify

\frac{5 + 1}{( cot ( q ) )} : 6 tan (q)

= \frac{d}{d q} (6 tan (q))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d q} (tan (q))

Apply the common derivative:

\frac{d}{d q} (tan (q)) = sec^{2} (q)

= 6 sec^{2} (q)

f (x) = 3 cos (x) - 4 sec (x) + 3

\frac{d}{d z} ((8 x^{3} + 3)^{4} x^{5} z^{2})

\frac{10 x + x ^{2}}{2}

f (x) = x \cdot 2 x

f (x) = - 7 x^{6}

What is the d/(dq)((5+1)/((cot(q)))) ?
The d/(dq)((5+1)/((cot(q)))) is 6sec^2(q)
What is the first d/(dq)((5+1)/((cot(q)))) ?
The first d/(dq)((5+1)/((cot(q)))) is 6sec^2(q)