What is the derivative of cos(x^2+y^2) ?

The derivative of cos(x^2+y^2) is -sin(x^2+y^2)(2x+2y(dy)/(dx))

What is the first derivative of cos(x^2+y^2) ?

The first derivative of cos(x^2+y^2) is -sin(x^2+y^2)(2x+2y(dy)/(dx))

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\frac{d}{d x} (cos (x^{2} + y^{2}))

- sin (x^{2} + y^{2}) (2 x + 2 y \frac{d y}{d x})

Solution steps

\frac{d}{d x} (cos (x^{2} + y^{2}))

Apply the chain rule:

- sin (x^{2} + y^{2}) \frac{d}{d x} (x^{2} + y^{2})

= - sin (x^{2} + y^{2}) \frac{d}{d x} (x^{2} + y^{2})

\frac{d}{d x} (x^{2} + y^{2}) = 2 x + 2 y \frac{d y}{d x}

= - sin (x^{2} + y^{2}) (2 x + 2 y \frac{d y}{d x})

y^{2} = 4 x, y = 2 x + 4

y = 3 - x, y = 9 - x^{2}

x \to 5 + lim (\frac{∣ 5 - x ∣}{5 - x})

y^{^{''}} + 9 y = - 30 sin (3 t)

\frac{d}{d x} (ln (sec (x) - tan (x)))

What is the derivative of cos(x^2+y^2) ?
The derivative of cos(x^2+y^2) is -sin(x^2+y^2)(2x+2y(dy)/(dx))
What is the first derivative of cos(x^2+y^2) ?
The first derivative of cos(x^2+y^2) is -sin(x^2+y^2)(2x+2y(dy)/(dx))