What is the derivative of (2x^2+3x+2)^5 ?

The derivative of (2x^2+3x+2)^5 is 5(2x^2+3x+2)^4(4x+3)

What is the first derivative of (2x^2+3x+2)^5 ?

The first derivative of (2x^2+3x+2)^5 is 5(2x^2+3x+2)^4(4x+3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

(2 x^{2} + 3 x + 2)^{5}

5 (2 x^{2} + 3 x + 2)^{4} (4 x + 3)

Solution steps

\frac{d}{d x} ((2 x^{2} + 3 x + 2)^{5})

Apply the chain rule:

5 (2 x^{2} + 3 x + 2)^{4} \frac{d}{d x} (2 x^{2} + 3 x + 2)

= 5 (2 x^{2} + 3 x + 2)^{4} \frac{d}{d x} (2 x^{2} + 3 x + 2)

\frac{d}{d x} (2 x^{2} + 3 x + 2) = 4 x + 3

= 5 (2 x^{2} + 3 x + 2)^{4} (4 x + 3)

\frac{( x - 1 ) ( x - 3 )}{( x - 2 ) ^{2}}

1 + sin^{2} (x)

2 e^{3} x

y = 2 x^{5}

\frac{d}{d a} (5 tan^{2} (a) - 5 sec^{2} (a) + 1)

What is the derivative of (2x^2+3x+2)^5 ?
The derivative of (2x^2+3x+2)^5 is 5(2x^2+3x+2)^4(4x+3)
What is the first derivative of (2x^2+3x+2)^5 ?
The first derivative of (2x^2+3x+2)^5 is 5(2x^2+3x+2)^4(4x+3)