What is the derivative of 2x^3-3 ?

The derivative of 2x^3-3 is 6x^2

What is the first derivative of 2x^3-3 ?

The first derivative of 2x^3-3 is 6x^2

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derivative of

2 x^{3} - 3

6 x^{2}

Solution steps

\frac{d}{d x} (2 x^{3} - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (3)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (3) = 0

= 6 x^{2} - 0

Simplify

= 6 x^{2}

\frac{1}{2 x}

3 ln (e^{x})

y = sin^{3} (1 - 2 x)

(x^{2} + 1)^{\frac{1}{2}} - 1

\frac{1}{sin ( x - y )}