What is the derivative of f(x)=x^3-x^2+4,k(x)=-2 ?

The derivative of f(x)=x^3-x^2+4,k(x)=-2 is 3x^2-2x

What is the first derivative of f(x)=x^3-x^2+4,k(x)=-2 ?

The first derivative of f(x)=x^3-x^2+4,k(x)=-2 is 3x^2-2x

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derivative of

f (x) = x^{3} - x^{2} + 4, k (x) = - 2

3 x^{2} - 2 x

Solution steps

\frac{d}{d x} (x^{3} - x^{2} + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4) = 0

= 3 x^{2} - 2 x + 0

Simplify

= 3 x^{2} - 2 x

\frac{ln ^{2} ( x )}{x}

(- 1)^{x}

(lo g_{10} (x))^{2}

5 x^{2} - 3 x + 4

sin^{23} (x)

What is the derivative of f(x)=x^3-x^2+4,k(x)=-2 ?
The derivative of f(x)=x^3-x^2+4,k(x)=-2 is 3x^2-2x
What is the first derivative of f(x)=x^3-x^2+4,k(x)=-2 ?
The first derivative of f(x)=x^3-x^2+4,k(x)=-2 is 3x^2-2x