What is the derivative of 1/(e^2x) ?

The derivative of 1/(e^2x) is -1/(e^2x^2)

What is the first derivative of 1/(e^2x) ?

The first derivative of 1/(e^2x) is -1/(e^2x^2)

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derivative of

\frac{1}{e ^{2} x}

- \frac{1}{e ^{2} x ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{e ^{2} x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{e ^{2}} \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{e ^{2}} \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{e ^{2}} (- 1 \cdot x^{- 1 - 1})

Simplify

\frac{1}{e ^{2}} (- 1 \cdot x^{- 1 - 1}) : - \frac{1}{e ^{2} x ^{2}}

= - \frac{1}{e ^{2} x ^{2}}

2 arctan (\frac{x}{2})

d (4 x^{15}) (8 x^{3})

y = \frac{6 sinh ( x )}{3}

y = \frac{x ^{3}}{3} + \frac{x ^{2}}{2} + \frac{x}{4}

y (1 - x^{2})

What is the derivative of 1/(e^2x) ?
The derivative of 1/(e^2x) is -1/(e^2x^2)
What is the first derivative of 1/(e^2x) ?
The first derivative of 1/(e^2x) is -1/(e^2x^2)