What is the derivative of y=ln((x+3)^2) ?

The derivative of y=ln((x+3)^2) is 2/(x+3)

What is the first derivative of y=ln((x+3)^2) ?

The first derivative of y=ln((x+3)^2) is 2/(x+3)

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derivative of

y = ln ((x + 3)^{2})

\frac{2}{x + 3}

Solution steps

\frac{d}{d x} (ln ((x + 3)^{2}))

Apply the chain rule:

\frac{1}{( x + 3 ) ^{2}} \frac{d}{d x} ((x + 3)^{2})

= \frac{1}{( x + 3 ) ^{2}} \frac{d}{d x} ((x + 3)^{2})

\frac{d}{d x} ((x + 3)^{2}) = 2 (x + 3)

= \frac{1}{( x + 3 ) ^{2}} \cdot 2 (x + 3)

Simplify

\frac{1}{( x + 3 ) ^{2}} \cdot 2 (x + 3) : \frac{2}{x + 3}

= \frac{2}{x + 3}

\frac{d}{d q} (- 4 \frac{q}{300} + 34)

\frac{2 x y}{( x ^{2} + y ^{2} )}

\frac{d}{d x} (- (x + p)^{2} + a)

\frac{1}{( 1 - t ^{2} )}

5 e^{3} x

What is the derivative of y=ln((x+3)^2) ?
The derivative of y=ln((x+3)^2) is 2/(x+3)
What is the first derivative of y=ln((x+3)^2) ?
The first derivative of y=ln((x+3)^2) is 2/(x+3)