What is the derivative of (x^3+4x)^3 ?

The derivative of (x^3+4x)^3 is 3(x^3+4x)^2(3x^2+4)

What is the first derivative of (x^3+4x)^3 ?

The first derivative of (x^3+4x)^3 is 3(x^3+4x)^2(3x^2+4)

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derivative of

(x^{3} + 4 x)^{3}

3 (x^{3} + 4 x)^{2} (3 x^{2} + 4)

Solution steps

\frac{d}{d x} ((x^{3} + 4 x)^{3})

Apply the chain rule:

3 (x^{3} + 4 x)^{2} \frac{d}{d x} (x^{3} + 4 x)

= 3 (x^{3} + 4 x)^{2} \frac{d}{d x} (x^{3} + 4 x)

\frac{d}{d x} (x^{3} + 4 x) = 3 x^{2} + 4

= 3 (x^{3} + 4 x)^{2} (3 x^{2} + 4)

9 cos^{3} (x)

(2 x^{2} + 9)^{3}

4 x + 5

\frac{d}{d x} (\frac{x ^{2} + x + m ^{2}}{x + 1})

6 cos (\frac{x}{2})

What is the derivative of (x^3+4x)^3 ?
The derivative of (x^3+4x)^3 is 3(x^3+4x)^2(3x^2+4)
What is the first derivative of (x^3+4x)^3 ?
The first derivative of (x^3+4x)^3 is 3(x^3+4x)^2(3x^2+4)