What is the derivative of y=-e^x(x^2-2x+3) ?

The derivative of y=-e^x(x^2-2x+3) is -e^xx^2-e^x

What is the first derivative of y=-e^x(x^2-2x+3) ?

The first derivative of y=-e^x(x^2-2x+3) is -e^xx^2-e^x

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derivative of

y = - e^{x} (x^{2} - 2 x + 3)

- e^{x} x^{2} - e^{x}

Solution steps

\frac{d}{d x} (- e^{x} (x^{2} - 2 x + 3))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (e^{x} (x^{2} - 2 x + 3))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = e^{x}, g = x^{2} - 2 x + 3

= - (\frac{d}{d x} (e^{x}) (x^{2} - 2 x + 3) + \frac{d}{d x} (x^{2} - 2 x + 3) e^{x})

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (x^{2} - 2 x + 3) = 2 x - 2

= - (e^{x} (x^{2} - 2 x + 3) + (2 x - 2) e^{x})

Simplify

- (e^{x} (x^{2} - 2 x + 3) + (2 x - 2) e^{x}) : - e^{x} x^{2} - e^{x}

= - e^{x} x^{2} - e^{x}

f (x) = \frac{1}{7 e ^{- 4} x}

lo g_{10} (\frac{1 + x}{n})

\frac{x ^{2}}{a ^{2}}

3 sin^{2} (x) + 3 cos^{2} (x)

\frac{ln ( x ^{2} )}{2}

What is the derivative of y=-e^x(x^2-2x+3) ?
The derivative of y=-e^x(x^2-2x+3) is -e^xx^2-e^x
What is the first derivative of y=-e^x(x^2-2x+3) ?
The first derivative of y=-e^x(x^2-2x+3) is -e^xx^2-e^x