What is the derivative of x=7t^2-t+4 ?

The derivative of x=7t^2-t+4 is 14t-1

What is the first derivative of x=7t^2-t+4 ?

The first derivative of x=7t^2-t+4 is 14t-1

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derivative of

x = 7 t^{2} - t + 4

14 t - 1

Solution steps

\frac{d}{d t} (7 t^{2} - t + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (7 t^{2}) - \frac{d t}{d t} + \frac{d}{d t} (4)

\frac{d}{d t} (7 t^{2}) = 14 t

\frac{d t}{d t} = 1

\frac{d}{d t} (4) = 0

= 14 t - 1 + 0

Simplify

= 14 t - 1

h (t) = (3 + 14 t - 5 t^{2})

f (q, r) = \frac{( q - a )}{r ^{2}}

y = \frac{x ^{2}}{( x + 1 )}

y = (x + 2)^{2}

\frac{d}{d x} (\frac{1}{( a \cdot cos ( x ) + b \cdot sin ( x ) )})

What is the derivative of x=7t^2-t+4 ?
The derivative of x=7t^2-t+4 is 14t-1
What is the first derivative of x=7t^2-t+4 ?
The first derivative of x=7t^2-t+4 is 14t-1