What is the first derivative of y-x^2+1 ?

The first derivative of y-x^2+1 is 1

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derivative of y-x^2+1

derivative of

y - x^{2} + 1

1

Solution steps

\frac{d}{d y} (y - x^{2} + 1)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d y}{d y} - \frac{d}{d y} (x^{2}) + \frac{d}{d y} (1)

\frac{d y}{d y} = 1

\frac{d}{d y} (x^{2}) = 0

\frac{d}{d y} (1) = 0

= 1 - 0 + 0

Simplify

= 1

6 x^{2} - 1

y = \frac{x + 1}{( x + 2 ) ^{2}}

(x^{2} + 3)^{4} (x^{2} + 5)^{2}

\frac{d}{d t} (50 + 4 t)

(e^{9 x})^{2}