What is the derivative of 9e^{-3}x^2 ?

The derivative of 9e^{-3}x^2 is (18x)/(e^3)

What is the first derivative of 9e^{-3}x^2 ?

The first derivative of 9e^{-3}x^2 is (18x)/(e^3)

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derivative of

9 e^{- 3} x^{2}

\frac{18 x}{e ^{3}}

Solution steps

\frac{d}{d x} (9 e^{- 3} x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 e^{- 3} \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 9 e^{- 3} \cdot 2 x^{2 - 1}

Simplify

9 e^{- 3} \cdot 2 x^{2 - 1} : \frac{18 x}{e ^{3}}

= \frac{18 x}{e ^{3}}

\frac{x + 1 - 4}{( - x + 3 )}

1 + 7 x

5 x^{2} + 9 x + c

3 x^{2} - 2 x + 4

f (x) = 3 x^{- 1}

What is the derivative of 9e^{-3}x^2 ?
The derivative of 9e^{-3}x^2 is (18x)/(e^3)
What is the first derivative of 9e^{-3}x^2 ?
The first derivative of 9e^{-3}x^2 is (18x)/(e^3)