What is the derivative of y=3sin(3x+7) ?

The derivative of y=3sin(3x+7) is 9cos(3x+7)

What is the first derivative of y=3sin(3x+7) ?

The first derivative of y=3sin(3x+7) is 9cos(3x+7)

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derivative of

y = 3 sin (3 x + 7)

9 cos (3 x + 7)

Solution steps

\frac{d}{d x} (3 sin (3 x + 7))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (sin (3 x + 7))

Apply the chain rule:

cos (3 x + 7) \frac{d}{d x} (3 x + 7)

= cos (3 x + 7) \frac{d}{d x} (3 x + 7)

\frac{d}{d x} (3 x + 7) = 3

= 3 cos (3 x + 7) \cdot 3

Simplify

= 9 cos (3 x + 7)

4 x^{3} - 9 x^{2} + 28 x - 68

\frac{y}{( 3 y ^{2} - x )}

\frac{x}{( x ^{2} + a ^{2} )}

\frac{1 - 1}{x}

3 ln (6 x + 1)

What is the derivative of y=3sin(3x+7) ?
The derivative of y=3sin(3x+7) is 9cos(3x+7)
What is the first derivative of y=3sin(3x+7) ?
The first derivative of y=3sin(3x+7) is 9cos(3x+7)