What is the derivative of sin(log_{10}(1+x)) ?

The derivative of sin(log_{10}(1+x)) is (cos(log_{10}(1+x)))/(ln(10)(1+x))

What is the first derivative of sin(log_{10}(1+x)) ?

The first derivative of sin(log_{10}(1+x)) is (cos(log_{10}(1+x)))/(ln(10)(1+x))

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derivative of

sin (lo g_{10} (1 + x))

\frac{cos ( lo g _{10} ( 1 + x ) )}{ln ( 10 ) ( 1 + x )}

Solution steps

\frac{d}{d x} (sin (lo g_{10} (1 + x)))

Apply the chain rule:

cos (lo g_{10} (1 + x)) \frac{d}{d x} (lo g_{10} (1 + x))

= cos (lo g_{10} (1 + x)) \frac{d}{d x} (lo g_{10} (1 + x))

\frac{d}{d x} (lo g_{10} (1 + x)) = \frac{1}{ln ( 10 ) ( 1 + x )}

= cos (lo g_{10} (1 + x)) \frac{1}{ln ( 10 ) ( 1 + x )}

Simplify

cos (lo g_{10} (1 + x)) \frac{1}{ln ( 10 ) ( 1 + x )} : \frac{cos ( lo g _{10} ( 1 + x ) )}{ln ( 10 ) ( 1 + x )}

= \frac{cos ( lo g _{10} ( 1 + x ) )}{ln ( 10 ) ( 1 + x )}

y = (1 - x^{3}) \cdot (1 + x^{3})

cos (7) x^{2}

(e^{x})^{2} + 2 ln (x^{e})

\frac{d}{d x} ((x^{3} - 3 x^{2} + 3 x + 1)^{^{'}} - (x - 1)^{^{'}})

(x - 1)^{3} (x + 1)^{2}

What is the derivative of sin(log_{10}(1+x)) ?
The derivative of sin(log_{10}(1+x)) is (cos(log_{10}(1+x)))/(ln(10)(1+x))
What is the first derivative of sin(log_{10}(1+x)) ?
The first derivative of sin(log_{10}(1+x)) is (cos(log_{10}(1+x)))/(ln(10)(1+x))