What is area x=-2,x=2,y=4x,y=x^2-5 ?

The answer to area x=-2,x=2,y=4x,y=x^2-5 is 64/3

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area x=-2,x=2,y=4x,y=x^2-5

area

x = - 2, x = 2, y = 4 x, y = x^{2} - 5

\frac{64}{3}

Decimal Notation

21.33333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{2} 4 x - (x^{2} - 5) d x

Solve

\int_{- 2}^{2} 4 x - (x^{2} - 5) d x : \frac{64}{3}

The area is:

= \frac{64}{3}

t^{2}

\frac{d}{d x} (2^{- x^{2}})

\frac{s + 3}{s ^{2} + 6 s + 13}

\frac{d}{d x} (x \times lo g_{10} (x))

\int tan^{3} (x) sec^{10} (x) d x

What is area x=-2,x=2,y=4x,y=x^2-5 ?
The answer to area x=-2,x=2,y=4x,y=x^2-5 is 64/3