What is the first derivative of e^2+x ?

The first derivative of e^2+x is 1

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derivative of e^2+x

derivative of

e^{2} + x

1

Solution steps

\frac{d}{d x} (e^{2} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{2}) + \frac{d x}{d x}

\frac{d}{d x} (e^{2}) = 0

\frac{d x}{d x} = 1

= 0 + 1

Simplify

= 1

∣ x + 2 ∣ - 2

\frac{1}{( x ^{2} - 1 )}

\frac{d}{df} (f (1) + f (- 2))

y = lo g_{10} (sin^{2} (x))

sin^{54} (x) + tan^{37} (x)